40: Perform a postorder traversal of a binary tree.
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Question:-

Perform a postorder traversal of a binary tree.
Example 1:
Input:
according to the question
Output:
Postorder traversal of binary tree is
4 5 2 3 1

Steps to solve:-

1. struct Node:-
This structure represents a binary tree node. Each node has an integer data value and two child pointers (left and right).
2. Node* newNode(int data):-
This is a utility function to create a new node for the binary tree. It takes an integer data as an argument, allocates memory for a new node, sets its data value, and initializes its child pointers to NULL. It returns a pointer to the newly created node.
3. void printPostorder(struct Node* node):-
This function performs a postorder traversal of the binary tree. In a postorder traversal, the left subtree is explored first, followed by the right subtree, and then the current node. The function takes a pointer to a Node as an argument.
4. int main():-
The main function is the entry point of the program. Inside main, a binary tree is created, and the printPostorder function is called to print the postorder traversal of the tree.
5. Creating the binary tree:-
In main, a binary tree is created with the following structure:
Root node (with data 1)
Left child of the root (with data 2)
Left child of node 2 (with data 4)
Right child of node 2 (with data 5)
Right child of the root (with data 3)
6 Printing the postorder traversal:-
After constructing the binary tree, the printPostorder function is called with the root node as an argument to print the postorder traversal. The postorder traversal output is displayed, showing the order in which the nodes are visited, following the "bottom-up" approach.

solution->

View Code 1
Time Complexity = O(n)
Space Complexity = O(1)